Question

cosec^2 30+sin^2 45+cos^2 60?​

Answer 1

Answer:

Hello mate,

Here is your solution :-

2^2 + (1/root2)^2 +(1/2)^2= 4+1/2+1/4= (16+2+1)/4=19/4 ans.

Thank you! !

Answer 2

Answer:

$\large\bold\red{\frac{19}{4}}$

Step-by-step explanation:

Given,

${ \cosec }^{2} 30 + { \sin }^{2} 45 + { \cos }^{2} 60$

Now,

we know that,

$\cosec(30) = 2 \\ \\ \sin(45) = \frac{1}{ \sqrt{2} } \\ \\ and \\ \\ \cos(60) = \frac{1}{2}$

Therefore,

we get,

${ \cosec }^{2} 30 = {2}^{2} = 4 \\ \\ { \sin }^{2} 45 = { (\frac{1}{ \sqrt{2} } )}^{2} = \frac{1}{2} \\ \\ { \cos }^{2} 60 = {( \frac{1}{2}) }^{2} = \frac{1}{4}$

Therefore,

putting the values,

we get,

$= 4 + \frac{1}{2} + \frac{1}{4 } \\ \\ = \frac{(4 \times 4) + (1 \times 2) + ( 1\times 1)}{4} \\ \\ = \frac{16 + 2 + 1}{4} \\ \\ \frac{19}{4}$

Hence,

Value = $\large\bold{\frac{19}{4}}$