Math, asked by voukola, 1 year ago

cosec^2 67°-tan^2 23°/sec^2 20°-cot^2 70°

Answers

Answered by amigo3
17
cosec 67°^2 - cot (90° - 23°)^2/cosec (90° - 20°)^2 - cot 70°^2
cosec 67°^2 - cot 67°^2/cosec70°^2 - cot 70°^2
1/1
=1
Answered by srikarnaidu24
1

Answer:

cosec2 67o−tan2 23o=

1+cot2 67o−tan2 23[∵cosec2 θ=1+cot2 θ]=

1+cot2 (90o−23o)−tan2 23=

1+tan2 23o−tan2 23 =1+0=1

do the same for denominator

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