Question

cosec^2 A =4xy/x^2+y^2 then relationship between x and y​

Answer 1

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☆Let cosec² have a real value

Therefore,

$\csc( {}^{2} )a \geqslant 1$

Now, putting value of cosec²

cosec²A=4xy/x²+y²

=>1=4xy/x²+y²

=>x²+y²=4xy

=>x²+y²-2xy=2xy

=>(x-y)²=2xy

=>x-y=√2xy.

=>X=√2xy+y

$\fbox\color{</em></strong><strong><em>black</em></strong><strong><em>}{</em></strong><strong><em> </em></strong><strong><em>=>X=</em></strong><strong><em>root</em></strong><strong><em>2xy+y</em></strong><strong><em> </em></strong><strong><em>}$

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