Question

cosecπ/2-theeta ==
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please answer it??​

Answer 1

Answer:

Step-by-step explanation:

Given: The expression  cosec(π/2+x) + y cos x cot (π/2+x) = sin(π/2 + x)​

To find: The value of y.

Solution:

Now we have given cosec(π/2+x) + y cos x cot (π/2+x) = sin(π/2 + x)​

We know :

             cosec (π/2+x) = sec x

             cot (π/2+x) = - tan x

             sin(π/2 + x)​ = cos x

So substituting this, we get:

             sec x + y cos x (- tan x) = cos x

             sec x + y cos x (- sin x / cos x) = cos x

             sec x - y sin x = cos x

             sec x - cos x = y sin x

             1/cos x - cos x = y sin x

             1 - cos^2 x = y sin x cos x

             sin^2 x = y sin x cos x

             sin x = y cos x

             y = sin x / cos x

             y = tan x

Answer:

          So the value of y is tan x.