Question

Cosec ²45 Sec ²30) (Sin² 30° +4 Cot² 45°- sec²6o]​

Answer 1

Answer: (cosec² 45° · sec² 30°)(sin² 30° + 4 cot² 45° - sec² 60°) = 2/3.

Explanation:

(cosec² 45° · sec² 30°)(sin² 30° + 4 cot² 45° - sec² 60°)

= (√2)² × (2/√3)² [(1/2)² + 4(1)² - 2²)]

= 2 × 4/3 (1/4 + 4 - 4)

= 8/3(1/4)

= 2/3

More: In advance cases, radians are used in place of degree. [Circular system.]

1ᶜ = 180°/π or simply, 2πᶜ = 360°.

So, you can now solve:

(cosec² π/4 · sec² π/3)(sin² π/6 + 4 cot² π/4 - sec² π/3).

Other systems:

• Sexagesimal system:

Here, 1° = 60′ (60 minutes)

1′ = 60″ (60 seconds.)

• Grade system:

90° = 100′ (100 minutes)

1′ = 100″ (100 seconds).

RELATIONSHIP B/W CIRCULAR/SEXAGESIMAL/GRADE SYSTEM:

D/90° = G/100 = 2C/π.

Answer 2

Answer:

4 (sin 60° + cos* 30°) -3 (tan² 60° - tan² 45°) + 5cos² 45°