Math, asked by mukuterrahman, 9 months ago

cosec 30° + cosec 60° + cosec90°
(vi)
sec 0° + sec 30° + sec 60°
choice :​

Answers

Answered by abhijeet6574
4

Answer:

1.

 \cosec(30)  +  \cosec(60)  +  \cosec(90)  \\  = 2 +  \frac{2}{ \sqrt{3} }  + 1 \\  =  \frac{2 \sqrt{3}  + 2 +  \sqrt{3} }{ \sqrt{3} }  =  \frac{3 \sqrt{ 3}  + 2}{ \sqrt{3} }

2.

 \sec(0)  +  \sec(30)  +  \sec(60)  \\  = 1 +  \frac{2}{ \sqrt{3} }  + 2 \\  =   \frac{ \sqrt{3}  + 2 + 2 \sqrt{3} }{ \sqrt{3} }  \\  =  \frac{3 \sqrt{3} + 2 }{ \sqrt{3} }

For this you need to remember the values of t-ratios.

Hope this helps mate...

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