Question

cosec 30° + cosec 60° + cosec90°
(vi)
sec 0° + sec 30° + sec 60°
choice :​

Answer 1

Answer:

1.

$\cosec(30) + \cosec(60) + \cosec(90) \\ = 2 + \frac{2}{ \sqrt{3} } + 1 \\ = \frac{2 \sqrt{3} + 2 + \sqrt{3} }{ \sqrt{3} } = \frac{3 \sqrt{ 3} + 2}{ \sqrt{3} }$

2.

$\sec(0) + \sec(30) + \sec(60) \\ = 1 + \frac{2}{ \sqrt{3} } + 2 \\ = \frac{ \sqrt{3} + 2 + 2 \sqrt{3} }{ \sqrt{3} } \\ = \frac{3 \sqrt{3} + 2 }{ \sqrt{3} }$

For this you need to remember the values of t-ratios.

Hope this helps mate...