Math, asked by pantry4, 1 year ago

Cosec 39*cos51+tan 21*cot 69-sec21


Answers

Answered by GauravGumber
14

cosec(90-51)cos51+tan21 tan(90-21)-sec21
=sec21 cos21+ tan21 cot21-sec21
=(1/cos21)*cos21+tan21*(1/tan21)-sec21
=1+1-sec21
=2-sec21
Answered by pinquancaro
11

Answer:

\csc 39\times cos 51+\tan21\times \cot 69-\sec^2 21=0

Step-by-step explanation:

Given : Expression \csc 39\times cos 51+\tan21\times \cot 69-\sec^2 21

To find : Solve the expression ?

Solution :

Expression \csc 39\times cos 51+\tan21\times \cot 69-\sec^2 21

=\csc (90-51)\times cos 51+\tan21\times \cot (90-21)-\sec^2 21

=\sec 51\times cos 51+\tan21\times \tan21-\sec^2 21

=\frac{1}{\cos 51}\times cos 51+\tan^2 21-\sec^2 21

We know, \tan^2\theta-\sec^2\theta=1

=1-1

=0

Therefore, \csc 39\times cos 51+\tan21\times \cot 69-\sec^2 21=0

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