Math, asked by db319648, 4 months ago

cosec 60°
sin 30° + tan 45º
(iv)
sec 30° + cos 60° + cot 45°​

Answers

Answered by Oneioiic14
1

\huge \sf {\purple{\underline {\pink {\underline { Answer᭄\ }}}}}

sec 30° + cos 60° + cot 45°

Sec 30° = 2/√3

Cos 60° = 1/2

Cot 45° = 1

Putting the values ,

= 2 /√3 + 1 / 2 + 1

= 2 /√3 + 1 + 2 / 2

= 2 /√3 + 3 / 2

= 2√3 +3 / 2

\sf\red{↠} 4 + 3√3 / 2√3

{\huge{\underline{\small{\mathbb{\red{HOPE\:IT\:HELPS\:UH :)}}}}}}

Answered by queenformyself
1

sec300+cos600+cot450sin300+tan450−cosec600

=32+21+121+1−32=23+3223−32×(23−32)(23−32

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