cosec[65 degree+a]-sec[25 degree-a]=0.solve it without using tringnometric table
Answers
Answered by
17
LHS: cosec(65+a) - sec(25-a)
= sec(90-(65+a))-sec(25-a)
= sec(90-65-a)-sec(25-a)
= sec(25-a)-sec(25-a)
= 0 which is RHS
therefore, LHS=RHS
i.e., Cosec[65 degree+a]-sec[25 degree-a]=0
Hence, it is proved.
= sec(90-(65+a))-sec(25-a)
= sec(90-65-a)-sec(25-a)
= sec(25-a)-sec(25-a)
= 0 which is RHS
therefore, LHS=RHS
i.e., Cosec[65 degree+a]-sec[25 degree-a]=0
Hence, it is proved.
himlu:
thanyou you
Similar questions