Question

cosec[65 degree+a]-sec[25 degree-a]=0.solve it without using tringnometric table

Answer 1

LHS:     cosec(65+a) - sec(25-a)
          = sec(90-(65+a))-sec(25-a)
          = sec(90-65-a)-sec(25-a)
          = sec(25-a)-sec(25-a)
          = 0 which is RHS

therefore, LHS=RHS
i.e., Cosec[65 degree+a]-sec[25 degree-a]=0
Hence, it is proved.