Question

Cosec 65 + theta minus sec 25 minus theta minus tan 55 - theta + cot 35 + theta

Answer 1

Answer:

QUESTION:-

Cosec65°-Sec25°-tan55°+cot35°

Step-by-step explanation:

Solution:-

Cosec65°=Sec(90-65)°

Tan55°=Cot(90-55)°

Sec25°-Sec25°+Cot35-Cot35=0

[Sec25°-Sec25°=0]

[Cot35°-Cot35°=0]

(°•°0+0=0)

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Answer 2

$\huge\mathbb{SOLUTION:-}$

$\sf\underline{\blue{Given:-}}$

$\sf cosec 65{}^{\circ}-sec25{}^{\circ}-tan65{}^{\circ}+cot 35{}^{\circ}$

$\sf\underline{\pink{\:\:\:\:\:\: Solution:-\:\:\:\:\:\:\:}}$

• we know that

$\sf sec \theta=cosec(90{}^{\circ}-\theta)\\ \\ \sf \:\: cot\theta= tan(90{}^{\circ}-\theta)$

• Now ATQ :-

$\sf\implies cosec65{}^{\circ}-sec(90-65{}^{\circ})-tan55{}^{\circ}+cot(90{}^{\circ}-55{}^{\circ})\\ \\ \sf\implies cosec65{}^{\circ}-cosec65{}^{\circ}-tan55{}^{\circ}+tan55{}^{\circ}\\ \\ \sf\implies 0-0\\ \\ \bf\implies 0$

• The answer is 0