Math, asked by sudhirdhakal07, 6 months ago

cosec^6A-cot^6A=1+3cosec^2Acot^2A

Answers

Answered by nehaimadabathuni123
0

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Answered by choudharyadarsh777
2

Step-by-step explanation:

cosec⁶A - cot⁶A = 1+ 3 cosec²A . cot²A

Taking LHS,

cosec⁶A - cot⁶A

= (cosec²A)³ - (cot²A)³

= (cosec²A - cot²A)³+3 cosec²A . cot²A (cosec²A-cot²A)

[ a³-b³= (a-b)³+3ab(a-b) ]

= (1)³+3 cosec²A . cot²A. (1)

= 1 + 3 cosec²A . cot²A = RHS

[ As 1 + cot²x = cosec²x ]

[ Then cosec²x - cot²x = 1 ]

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