cosec(75+°)-sec(15+°)
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Answered by
0
Answer:
0
Step-by-step explanation:
cosec(75
0
+θ)−sec(15
0
−θ)−tan(55
0
+θ)+cot(35
0
−θ)
=sec(90
0
−75
0
−θ)−sec(15
0
−θ)−cot(90
0
−55
0
−θ)+cot(35
0
−θ)
=sec(15
0
−θ)−sec(15
0
−θ)−cot(35
0
+θ)+cot(35
0
+θ)
=0
Answered by
1
Answer:
Cosec(90°-15°)-sec(15)
sec 15°- sec 15°
0
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