[cosec(750+A)-sec (150-A)-tan (550+A) +cot (350-A)]
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Answer:
Step-by-step explanation:
cosec (75
0
+θ)−sec(15
0
−θ)−tan(55
0
+θ)+cot(35
0
−θ)
As, we know that,
cosec θ=sec(90
0
−θ) and
tanθ=cot(90
0
−θ)
Using these, we get
E=sec(90
0
−75
0
−θ)−sec(15
0
−θ)−cot(90
0
−55
0
−θ)+cot(35
0
−θ)
⇒E=sec(15
0
−θ)−sec(15
0
−θ)−cot(35
0
−θ)+cot(35
0
−θ)=0
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