CBSE BOARD XII, asked by wafulamoses36, 1 year ago

cosec(75°+ø)-sec(15°-ø)

Answers

Answered by writersparadise
6

The basic formula used here is cosec (90° - ∅) = sec .


Thus, cosec(75° + ∅) – sec(15° - ∅) = cosec((90° - 15°) + ∅) – sec(15° - ∅)

                                                         

                                                         = cosec(90° - (15° - ∅)) - – sec(15° - ∅)

                                                         

                                                         = sec(15° - ∅) – sec(15° - ∅)

        
Thus,  cosec(75° +
∅) – sec(15° - ∅)  = 0.
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