(cosec(90-Q)-sin(90-Q))(cosQ-sinQ)(tanQ+cotQ)=1
Please prove fast
Answers
Answered by
0
Answer:
cot (90-Q)/tanQ+cosec (90-Q)sinQ/tan(90-Q)
= tanQ/tanQ+secQ*sinQ/cotQ
= 1+1/cosQ*sinQ/cosQ/sinQ
=1+1/cosQ*sin^{2}Q/cosQ
=1+sin^{2}Q/cos^{2}Q
=sec^{2}Q
Similar questions
Math,
5 months ago
Social Sciences,
5 months ago
English,
5 months ago
Biology,
11 months ago
Social Sciences,
11 months ago
Math,
1 year ago