Math, asked by mohitpatil07057, 2 months ago

{Cosec (90-θ) - Sin (90-θ)} {(Cosecθ - Sin θ) (tanθ + cotθ)} = 1​

Answers

Answered by studarsani18018
1

Answer:

2

Step-by-step explanation:

As we know that,

sin(90

o

−θ)=cosθ, cos(90

o

−θ)=sinθ,

cosec(90

o

−θ)=secθ, cot(90

o

−θ)=tanθ,

sec(90

o

−θ)=cosecθ, tan(90

o

−θ)=cotθ

cosec(90−θ)sin(90−θ)cot(90−θ)

cos(90−θ)sec(90−θ)tanθ

+

cotθ

tan(90−θ)

sin(90−θ)

1

×sin(90−θ)×tanθ

sinθ×

cos(90−θ)

1

×tanθ

+

cotθ

cotθ

=

cosθ

1

×cosθ

sinθ×

sinθ

1

+1

=1+1=2

Hence, 2 is the answer

Answered by aloqu
1

Step-by-step explanation:

hope it is helpful

trigonometric ratios

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