Question

cosec(90+x)+ cot(90+x)/cosec(90-x)+ tan(180-x)+ tan(180+x)+ sec(180-x)/tan(360+x)- sec(-x) = 2​

Answer 1

Answer:

$\frac{cosec(90+x)+ cot(90+x)}{cosec(90-x)+ tan(180-x)}+ \frac{tan(180+x)+ sec(180-x)}{tan(360+x)- sec(-x)}=2$

Step-by-step explanation:

Formula used:

cosec(90+A)=secA

cot(90+A)=-tanA

cosec(90-A)=secA

tan(180-A)=-tanA

tan(180+A)=tanA

sec(180-A)=-secA

sec(-A)=secA

$\frac{cosec(90+x)+ cot(90+x)}{cosec(90-x)+ tan(180-x)}+ \frac{tan(180+x)+ sec(180-x)}{tan(360+x)- sec(-x)}$

$=\frac{secx-tanx}{secx- tanx}+ \frac{tanx-secx}{tanx- secx}$

$=1+1$

$=2$