cosec (90°-A)=?
if in a triangle ABC,BC=DE,where AD=1.5cm,BD=3cm,AE =1cm
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Answer 1:Cosec(90-A) = sec A
In triangle ABC, DE is parallel to BC
Hence,
AD/DB=AE/EC
1.5/3=1/EC
1/2=1/EC
EC=2cm
⚜️I HOPE IT HELPS YOU ⚜️
Answer 1:Cosec(90-A) = sec A
In triangle ABC, DE is parallel to BC
Hence,
AD/DB=AE/EC
1.5/3=1/EC
1/2=1/EC
EC=2cm
⚜️I HOPE IT HELPS YOU ⚜️
prerona14:
tqqqq
nope, show it by giving a heart and marking it as brainliest!
how DE is parallel to BC
he didn't wrote the question fully
I have this question in my textbook
okay
ok
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