cosec (90°-O). sin (90° - 0) = 1
Answers
Answered by
0
Step-by-step explanation:
[cosec(90
∘
−θ)−sin(90
∘
−θ)][cosecθ−sinθ][tanθ+cotθ]
=(secθ−cosθ)(cosecθ−sinθ)
(
cosθ
sinθ
+
sinθ
cosθ
)
∵cosec(90
∘
−θ)=secθ
∵sin(90
∘
−θ)=cosθ
=(
cosθ
1
−cosθ)(
sinθ
1
−sinθ)(
sinθcosθ
sin
2
θ+cos
2
θ
)
=(
cosθ
1−cos
2
θ
)(
sinθ
1−sin
2
θ
)(
sinθcosθ
1
)
=(
cosθ
sin
2
θ
)(
sinθ
cos
2
θ
)(
sinθcosθ
1
)=1
here is ur answer
Answered by
0
Step-by-step explanation:
cosec(90°-O). sin(90°-O)=1
{1/sin(90°-O)}.sin(90°-O)=1
1.{sin(90°-O)/sin(90°-O)}=1
1=1
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