Math, asked by hemalatha2965, 4 months ago

[cosec(90°- theta)-sin(90°- theta)][cosec theta- sin theta][tan theta+cot theta]=1​

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Answered by vvk470
2

Answer:

sin(90o−θ)=cosθ, cos(90o−θ)=sinθ,

cosec(90o−θ)=secθ, cot(90o−θ)=tanθ,

sec(90o−θ)=cosecθ, tan(90o−θ)=cotθ

∴ cosec(90−θ)sin(90−θ)cot(90−θ)cos(90−θ)sec(90−θ)tanθ+cotθtan(90−θ)

∴ sin(90−θ)1×sin(90−θ)×tanθsinθ×cos(90−θ)1×tanθ+cotθcotθ

=cosθ1×cosθsinθ×sinθ1+1 

=1+1=2

Answered by sivaguru8556
1

Answer:

hi Hema

Which district are you from

Step-by-step explanation:

நீ எந்த ஊர்

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