Math, asked by priyanshusriva45, 4 days ago

cosec A/cosec A-1 + cosec A/cosec A+1=2 sec A

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Answered by PURVA0246

3

Given cosec θ+1cosec A+cosec A−1cosec A

Taking LCM

cosecA+1cosecA+cosec A−1cosec A=cosec2A−1cosec2A−cosec A+cosec2A+cosec A

=cosec2A−12cosec2A

As cosec2A−1=cot2A

=cot2A2cosec2A=sin2Acos2Asin2A2=

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