Cosec A = root 10, A+B=90. Find cos B.
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Answer:
A + B = 90°
=> A = 90° - B
cosec A = √10
cosec( 90° - B ) = √10 [ { cosec ( 90° - θ ) = sec θ } ]
sec B = √10 [ sec θ = 1/cosθ ]
cos B = 1 / √10
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