(cosec A + sin A)(cosec A - sin A ) = cot^2A + cos^2A
Prove .
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Answer:
Prove that:
(cosec A+sin A)(cosec A-sin A)=cot²A+cos²A
L.H.S=(cosec A+sin A)(cosec A-sin A)
=cosec²A -sin²A .....[(a+b)(a-b)=a²-b²]
=1+cot²A-(1-cos²A) .....(cosec²A=1+cot²A and
sin²A=1-cos²A)
=1+cot²A-1+cos²A
=cot²A+cos²A
therefore:
(cosec A + sin A)(cosec A-sin A)=cot²A+cos²A
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