Question

(cosec A - sin A) ( sec A - cos A) sec^2=tan A........ prove​

Answer 1

Step-by-step explanation:

cosecA = 1/sinA

secA = 1/cosA

put in equa.

((1-sin²A) /sinA) *((1-cos²A) /cosA) *sec²A

1-sin²A = cos²A

1-cos²A =sin²A

put in equa.

((cos²A) /sinA) *((sin²A) /cosA) sec²A

=> (cos²A*sin²A)/(sinAcosA) *sec²A

=> sinAcosA * (1/cos²A)

=> sinA/cosA

= tanA