(cosec A - sin A) ( sec A - cos A) sec^2=tan A........ prove
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Step-by-step explanation:
cosecA = 1/sinA
secA = 1/cosA
put in equa.
((1-sin²A) /sinA) *((1-cos²A) /cosA) *sec²A
1-sin²A = cos²A
1-cos²A =sin²A
put in equa.
((cos²A) /sinA) *((sin²A) /cosA) sec²A
=> (cos²A*sin²A)/(sinAcosA) *sec²A
=> sinAcosA * (1/cos²A)
=> sinA/cosA
= tanA
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