Math, asked by Riyaa691, 8 months ago

(cosec-cos)^2 = 1-cos/1+cos Prove it

Answers

Answered by pranavmofficial2005
1

Answer:

Step-by-step explanation:

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Answered by Skyllen
3

We can prove it in different way,

by solving RHS.

★[If you want any other method, then check my another answer:

https://brainly.in/question/18394752]

____________________________

Using Identity:

  • 1 - cos²Θ = sin²Θ
  • 1/sinΘ = cosecΘ
  • cosΘ/sinΘ = cotΘ

 \\

Answer:

 \tt \implies RHS =  \dfrac{1 - cos \theta}{1 + cos \theta}  \\  \\ \tt \implies RHS  = \dfrac{1 - cos \theta}{1 + cos \theta}  \times  \dfrac{1 - cos \theta}{1 - cos \theta} ....(rationalisation) \\  \\ \tt \implies RHS  =  \dfrac{1 -cos {}^{2}  \theta }{sin {}^{2}  \theta}  \\  \\ \tt \implies RHS = ( \dfrac{1 - cos \theta}{sin \theta} ) {}^{2}  ....(square \: common)\\  \\ \tt \implies RHS  = ( \frac{1}{sin \theta}  -  \dfrac{cos \theta}{sin \theta} ) {}^{2}  \\  \\ \tt \implies  RHS = (cosec \theta - cot \theta) {}^{2}

 \large \implies \boxed {\boxed {\tt \blue {RHS = LHS }}}

\\ \large\bold\red{\: \: \: \: \:  \: \: \: \: \: Hence \: \: Proved}

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