Question

(cosec-cot)2=1-cos÷1+cos

Answer 1

(cotθ-cosecθ)²

=cot²θ-2cotθcosecθ+cosec²θ

=cos²θ/sin²θ-2(cosθ/sinθ)(1/sinθ)+1/sin²θ

=cos²θ/sin²θ-2cosθ/sin²θ+1/sin²θ

=(cos²θ-2cosθ+1)/sin²θ

=(1-cosθ)²/(1-cos²θ)

=(1-cosθ)²/(1+cosθ)(1-cosθ)

=(1-cosθ)/(1+cosθ)

$\huge{thanks}$