Math, asked by tapasikower1234, 9 months ago

cosec θ – cot θ= sin⁡θ/(1+cos⁡θ )​

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Answered by TRISHNADEVI
2

 \huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \:   \: SOLUTION\:  \: } \mid}}}}}

 \mathtt{ L.H.S. = \frac{sin \:  \theta}{1 + cos \:   \theta} } \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \mathtt{ =\frac{sin \:  \theta \: (1 - cos \:  \theta)}{(1 + cos \:   \theta)(1 - cos \:  \theta)} }\\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \mathtt{ =  \frac{sin \:  \theta (1-  cos \:  \theta))}{1 - cos {}^{2} \theta } } \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \mathtt{ =  \frac{sin \:  \theta(1 - cos \:  \theta)}{sin {}^{2} \:  \theta } } \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \: \mathtt{ =  \frac{1 - cos \:  \theta}{sin \:  \theta} } \\  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:   \mathtt{ =  \frac{1}{sin \:  \theta}  -  \frac{cos \:  \theta}{sin \:  \theta} } \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \mathtt{ = cosec \:  \theta - sec \:  \theta} \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \: \mathtt{ = R.H.S.}

Answered by sreejabulusu
0

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