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Cosec - sin = a^3 and sec - cos = b^3 then find a^2b^2(a^2 + b^2)

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Gajaanan Muley

Sep 18, 2013

cosecθ-sinθ=a3, secθ-cosθ=b3, prove that a2b2(a2+b2)=1

if cosecθ-sinθ=a3, secθ-cosθ=b3, prove that a2b2(a2+b2)=1

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Kishore Kumar

Consider cosecθ – sinθ = a3 Now consider, secθ – cosθ=b3 Multiply (2) and (4), we get

Step-by-step explanation:

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