Math, asked by ribikanaik9195, 10 months ago

(Cosec-sin) (sec-cos) (tan+cot)

Answers

Answered by saisagar6129
5

Answer:

Step-by-step explanation:

(1/sin-sin)(1/cos-cos)(sin/cos-cos/sin)

(1-sin^2)/sin(1-cos^2)/cos(sin^2+cos^2)/sincos

(cos^2/sin)(sin^2/cos)(1/sincos)

cos x sin x 1/sincos

= 1

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