Math, asked by zoyakhan1669, 10 months ago

Cosec square 45 degrees secant square 30 degree sin square 30 degree + 4 cot square 45 degree minus secant square 60 degree

Answers

Answered by InfinityAlien
19

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Answered by pinquancaro
11

\csc^2 45^\circ \sec^2 30^\circ \sin^230^\circ+4\cot^2 45^\circ-\sec^2 60^\circ=\frac{2}{3}

Step-by-step explanation:

Given : Expression \csc^2 45^\circ \sec^2 30^\circ \sin^230^\circ+4\cot^2 45^\circ-\sec^2 60^\circ

To find : The value of the expression ?

Solution :

Expression \csc^2 45^\circ \sec^2 30^\circ \sin^230^\circ+4\cot^2 45^\circ-\sec^2 60^\circ

We know the trigonometric values,

\csc 45^\circ=\sqrt{2}\\\\\sec 30^\circ=\frac{2}{\sqrt{3}}\\\\\sin30^\circ= \frac{1}{2}\\\\\cot 45^\circ=1\\\\\sec 60^\circ=2\\\\

Substitute all,

=(\sqrt2)^2 (\frac{2}{\sqrt3})^2(\frac{1}{2})^2+4(1)^2-(2)^2

=(2)(\frac{4}{3})(\frac{1}{4})+4-4

=\frac{2}{3}

Therefore, \csc^2 45^\circ \sec^2 30^\circ \sin^230^\circ+4\cot^2 45^\circ-\sec^2 60^\circ=\frac{2}{3}

#Learn more

Evaluate the following sin 30 degrees + tan 45 degrees minus cos tan 60 degrees by cos 45 degrees + Cos 60 degrees minus secant 30 degrees​

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