Math, asked by revathi55, 1 year ago

cosec square 67 degree minus tan square 23 degree is​

Answers

Answered by SnehaG
11
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hello..!

→ cosec²67° - tan²23°

»cosec²ø = sec²(90° - ø)«

→ cosec²67° - tan²(90° - 67°)

→ cosec²67° - sec²67°

→ 1 ""@π$""

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→thankà←

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revathi55: i think it's wrong
revathi55: it's answer is 1
revathi55: kk... right
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Answered by pinquancaro
10

\csc^2 67-\tan^2 23=1

Step-by-step explanation:

Given : Expression \csc^2 67-\tan^2 23

To find : The value of the expression ?

Solution :

Expression \csc^2 67-\tan^2 23

We know, \tan(90-\theta)=\cot\theta

We can write,

\tan23=\tan(90-67)

\tan23=\cot 67

\tan^2 23=\cot^2 67

Substitute in the expression,

\csc^2 67-\tan^2 23=\csc^2 67-\cot^2 67

By trigonometric property,

\csc^2\theta+\cot^2\theta=1

\csc^2 67-\tan^2 23=1

#Learn more

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