Question

Cosec square theta+ root 3 cot theta -7=0

Answer 1

Answer:

we know,

$1 + {cot}^{2} theta = {cosec}^{2} \: theta$

1 + cot^2 theta + √3 cot theta - 7=0

let cot theta = x

(x)^2 + √3x - 6 = 0

↪(x )^2 +2√3x - √3x - 6 = 0

↪x ( x + 2√3 ) - √3 ( x + 2√3 ) = 0

↪( x - √3 ) ( x + 2√3 )

↪ x = √3 OR x = -2√3

Therefor

cot theta = √3 OR cot theta = -2/√3