cosec square thetha + cot square thetha = 5 then evaluate sec Thetha
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Step-by-step explanation:
We know that :
1 + (cot θ)^2 = (cosec θ)^2
So,
(cosec θ)^2 + (cot θ)^2 = 5
OR, (cosec θ)^2 + [1 + (cot θ)^2 ] = 6
OR, 2(cosec θ)^2 = 6
or, (cosec θ)^2 = 3
or,. (sin θ)^2 = 1/3
sin θ = 1/√3
cos θ = √(2/3)
sec θ = √(3/2)
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