Question

(cosec Teta-cot Teta) =1-cos teta/1+cos teta​

Answer 1

Step-by-step explanation:

LHS =1−cosA1+cosA

Multiplying numerator and denominator by 1 - cos A

=(1−cosA)(1−cosA)(1+cosA)(1−cosA)

=(1−cosA)21−cos2A [∵(a+b)(a−b)=a2−b2]

=(1−cosA)2sin2A [∵1−cos2A=sin2A]

=(1−cosAsinA)2

=(1sinA−cosAsinA)2

=(cosecA−cotA)2 [∵1sinA=cosecA,cosAsinA=cotA]

=[−1(cotA−cosecA)]2

= (cot A - cosec A)2

Hence proved.

Answer 2

Step-by-step explanation:

HEY MATE

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