Question

√cosec theta - 1/√ cosec theta + 1 + √cosec theta + 1/√cosec theta - 1 = 2 sec theta​

Answer 1

Answer:

Hi

Step-by-step explanation:

Hi ,

Here I used A instead of theta.

LHS= CosecA/(cosecA-1)+cosecA/(cosecA+1 )

= CosecA [1/(cosecA-1) +1/(Cosec A+1)]

= CosecA[(cosecA+1+cosec A -1)/(cosecA-1 )(cosec A+1 )]

= ( 2cosec²A ) / [ cosec² A - 1 ]

= 2cosec²A / cot² A

= 2 ( 1/sin² A ) / ( cos² A/sin² A )

= 2/cos² A

= 2sec²A

= RHS