Question

Cosec theta =3x and cot theta =3/x,then find the value of (x^2-1/x^2)

Answer 1

since it is given that 3x=cosec theta and 3/x=cot theta

so,x=cosec theta/3 & 1/x=cot theta/3

so,3(cosec theta^2/9 - cot^2/9)

3[1/9(cosec theta^2 - cot theta^2). -(1)

as we know that 1 + cot theta^2=cosec theta^2

1=cosec theta^2 - cot theta ^2. -(2)

putting value of (2) in (1)

1/3(1)

1/3

hope this helps....

and if it helps mark me as the brainliest.....