cosec theta+cot theta = 1/3, find sin theta
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Given that cosec∅ + cot∅ = 1/3......(1)
To find: sin∅
We know that,
cosec²∅ - cot²∅ = 1
→(cosec∅ + cot∅)(cosec∅ - cot∅) =1
→(cosec∅ - cot∅)/3 = 1 [From (1)]
→cosec∅ - cot∅ = 3..........(2)
Adding equations (1) and (2),we get:
2cosec∅ = 10/3
→cosec∅ = 5/3
We know that,
cosec∅ = 1/sin∅
→sin∅ = 3/5
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