Math, asked by imtiyaz15, 11 months ago

cosec theta + cot theta = 1 /cosec theta - cot theta prove that ​

Answers

Answered by rashmijaiswal2008
1

Answer:

The answer is in the attachment.

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Answered by diyasejwar
0

Answer:

Step-by-step explanation:Let. theta=x

(cosecx-cotx)=1/(cosecx-cotx)

or. (cosecx-cotx)^2=1

or. cosec^2(x)+cot^2(x)-2cosecx.cotC=1

or. cosec^2(x)-1+cot^2(x)-2cosec(x).cot(x)=0

or. cot^2(x)+cot^2(x)-2.cosec(x).cot(x)=0

or. 2.cot^2(x)-2.cosec(x).cot(x)=0

or. 2.cot(x){cot(x)-cosec(x)}=0

Either. cot x=0

cot x= cot π/2

or. x=π/2. Answer.

Or. cotx-cosecx=0

or cotx=cosecx

or. cosx/sinx=1/sinx

or. cosx=1

or. cosx=coso°

or. x=0°. Answer.

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Shreyas Waghe

Shreyas Waghe

Answered Sep 20, 2018

theta is a greek character represented as θ

cosec θ=1/sin θ

where sinθ= perpendicular/hypotenuse for a traingle where one angle is 90 and the base angle is θ,

Similarly, cot θ= 1/tan θ

where tan θ= sin(θ)/cos(θ)

cos θ=base/hypotenuse

Also,cosec²θ-cot²θ=1 not cosec θ-cot θ

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