Question

(cosec theta +cot theta)^2 =1+ sec /1- sec theta

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Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

first we will start from L.H.S

(cosecA+cotA)²

=(1/sinA)+(cosA/sinA)²

=(1+cosA/sinA)²

=(1+cosA)²/sin²A

=(1+cosA)²/1-cos²A

=(1+cosA)²/(1-cosA)(1+cosA)

=(1+cosA)/1-cosA

=1+(1/secA)/1-(1/secA)

=secA+1/secA-1

= R.H.S

L.H.S  = R.H.S

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