Cosec theta+cot theta=2 find cos theta
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cos ¤ =3/5
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cosec theta +cot theta =2
squaring on both sides
(cosec theta + cot theta) ^2 = 2^2
cosec ^2 theta + cot ^2 theta + 2cosec theta. cot theta =4
cosec ^2 theta + cosec ^2 theta –1+2 cos/sin^2 =4
2 cosec ^2 theta + 2 cos theta /sin ^2 theta = 4+1 2/sin^2 theta + 2 cos theta /sin^2 theta =5 (.. cosec^2 = 1/sin^2 )
2+2 cos theta /sin^2 theta =5
2(1+ cos theta) /(1-cos^2 theta) =5
2( 1+cos theta) /(1- cos theta) (1+ cos theta) cot =5
5x1- cos theta = 2
5x 5cos theta =2
5cos theta = 5-2
5cos theta =3
•°• cos theta =3/5
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