Question

(cosec theta + cot theta)² = sec theta +1/ sec theta -1​

Answer 1

Step-by-step explanation:

(cosecA+cotA)²

=(1/sinA+cosA/sinA)²

=(1+cosA/sinA)²

=(1+cosA)²/sin²A

=(1+cosA)²/1-cos²A

=(1+cosA)²/(1-cosA)(1+cosA)

=(1+cosA)/1-cosA

=1+(1/secA)/1-(1/secA)

=secA+1/secA-1

Answer 2

Step-by-step explanation:

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