Question

cosec theta minus cot theta ka whole square equals to 1 minus cos theta upon 1 + cos theta

Answer 1

(cosecA - cotA)^2 = 1-cosA/1+cosA

Lhs-

(1/sinA - cosA/sinA) ^2

(1-cosA/sinA)^2

(1-cosA)^2/ sin^2A

1+cos^2A -2cosA/sin^2A

Rhs-

1-cosA/1+cosA X 1-cosA/1-cosA

(1-cosA)^2/ 1-cos^2A

1+cos^2A-2cosA/sin^2A

LHS=RHS

Hence proved !

Answer 2

Answer:

Step-by-step explanation:

(Cosecx-cot)^2_(1/sinx-cosx/sinx)^2_(1-cosx/sinx)^2_sin^2/sin^2_1