Math, asked by navneethsharma6201, 1 year ago

(Cosec x /cosec x - 1) +( cosec x / cosec x + 1) = sec 2 x

Answers

Answered by tiger1123
1

Step-by-step explanation:

(cosec x /cosec x - 1) +( cosec x / cosec x + 1) = 2sec ²x

taking LHS

(cosec x /cosec x - 1) +( cosec x / cosec x + 1)

=[(cosec x *(cosec x + 1)) +(cosec x * (cosec x - 1)) ]/(cosec x+1)(cosec x-1)

=(cosec²x+cosec x+cosec²x-cosec x)/(cosec²x-1)

=(2 cosec² x)/cot² x

=(2* 1/sin² x)/(cos² x/sin² x)

=2/cos²x

=2 sec²x

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