Math, asked by shwethashivananda198, 2 days ago

cosec²(90-Θ)-tan²Θ /4(cos²40+cos²50) - 2tan²30.sec²52.sin²38/3[cosec²70-tan²20] = 1/36

Answers

Answered by kiranbhanot639

1

Answer:

$\frac{ - 5}{12} .$

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