Question

cosec2 (90°-0) - tan2 0= cos2 (90° - 0) + cos2 0​

Answer 1

cosec²(90°-∅)-tan²∅ = cos²(90°-∅)+cos²∅

sec²∅-tan²∅ = sin²∅+ cos²∅

(1/cos²∅)- (sin²∅/cos²∅) = 1

(1+cos²∅)/(sin²∅) = 1

1+cos²∅= sin²∅

Answer 2

kindly excuse my handwriting