cosec²(90°-theta)-tan²theta
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Answered by
9
Hi ,
Here I am using A instead of theta.
****************
We know that ,
1 ) Cosec ( 90 - A) = sec A
2 ) sec² A - tan² A = 1
*****************"**********
Cosec² ( 90 - A ) - tan² A
= Sec² A - tan² A
= 1
I hope this helps you.
:)
Here I am using A instead of theta.
****************
We know that ,
1 ) Cosec ( 90 - A) = sec A
2 ) sec² A - tan² A = 1
*****************"**********
Cosec² ( 90 - A ) - tan² A
= Sec² A - tan² A
= 1
I hope this helps you.
:)
Answered by
3
cosec²(90°-theta)-tan²theta
{cosec(90 - theta)= sec theta}
sec²theta -tan²theta
{ sec²theta-tan²theta = 1}
sec²theta -tan²theta =1
{cosec(90 - theta)= sec theta}
sec²theta -tan²theta
{ sec²theta-tan²theta = 1}
sec²theta -tan²theta =1
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