Math, asked by tanika, 9 months ago

cosec²θ / cosec θ -1 - cosec²θ / cosecθ + 1 = 2 sec²θ
prove it plsssssssssssssss

Answers

Answered by kabirsingh18
1

Answer:

Hey there

 =  \frac{ { \csc( \alpha ) }^{2} }{ \csc( \alpha ) - 1 }  -   \frac{ { \csc( \alpha ) }^{2} }{ \csc( \alpha )  + 1}  \\  =  \frac{  { \csc( \alpha ) }^{2}( \csc(  \alpha )   + 1) -  { \csc( \alpha ) }^{2}( \csc( \alpha )  - 1) }{( \csc(  \alpha )  + 1)( \csc( \alpha ) - 1) }  \\   =  \frac{ { \csc( \alpha ) }^{2} ( \csc( \alpha ) + 1 +  \csc( \alpha ) - 1)  }{ { \csc( \alpha ) }^{2}  - 1}  \\  =  \frac{ { \csc( \alpha )  }^{2}  \times 2 \csc( \alpha ) }{ { \cot( \alpha ) }^{2} }  \\  =  \frac{2 { \sin( \alpha ) }^{2} }{ { \sin( \alpha ) }^{3} {  \cos( \alpha )  }^{2}  }   \\  = 2 { \sec( \alpha ) }^{2}  \csc( \alpha )

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Answered by AdorableMe
1

Answer:

See the attachment.

Step-by-step explanation:

mark as the brainliest.....

Attachments:

mysticd: Last line 2sec²(theta)
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