Question

Cosec²57°-Tan²33° = ?​

Answer 1

Answer:

Cosec²57°-Tan²33°

= Cosec²(90-33)° - Tan²33°

= Sec²33° - Tan²33°

= 1 Ans (because,1 + tan²x = sec²x)

Hope This helps ☺️

Answer 2

$\blue{A}$ ${N}$ $\red{S}$$\orange{W}$$\green{E}$]$\pink{R}$→

Given→

cosec²57°-tan²33°

To find→

Evaluated value

Solution→

$→ \: {cosec}^{2} 57°-{tan}^{2} 33° \\ ({cosec}^{2} x = {sec}^{2}(90 - x)°) \\ = {sec}^{2} (90 - 57)° - {tan}^{2} 33° \\ = {sec}^{2} 33° - {tan}^{2} 33° \\ ( {sec}^{2} x - {tan}^{2} x = 1) \\ = 1$