Math, asked by saatvikaahegde, 7 months ago

cosec2theta /cosec theta-1 - cosec2theta/cosec theta +1 =2 sec 2 theta ​

Answers

Answered by itsbiswaa
3

Answer:

By taking Cosec^2 θ Common  

(Cosecθ)^2(1/Cosecθ-1 -1/Cosecθ+1)

(Cosecθ)^2(Cosecθ+1-Cosecθ + 1)/(Cosecθ)^2 - 1

(Cosecθ)^2)(2)/(Cotθ)^2

2(Cosecθ)^2(Tanθ)^2

2(Cosecθ *Tanθ)^2

2(Cosecθ * Secθ / Cosecθ)^2

2(Sec)^2

hope it helps u

Step-by-step explanation:

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