Math, asked by luckysingh1840, 4 months ago

Cosec30°+cosec60°+cosec9p0°
__________________________
Sec0°+sec30°+sec60°

Answers

Answered by chMalleshwari1111
1

Step-by-step explanation:

We know that

cosec30 = 2

cosec60 = 2/√3

cosec90 = 1

sec0° = 1

sec30= 2/√3

sec60°=2

substitute the above all values

2+2\√3 + 1/ 1+2/√3+2

3√3/3√3

= 1

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